diff --git a/20260109_160634_quadratic_vertex-ClaudeCode+Opus45/figure.png b/20260109_160634_quadratic_vertex-工具ClaudeCode模型Opus45/figure.png
similarity index 100%
rename from 20260109_160634_quadratic_vertex-ClaudeCode+Opus45/figure.png
rename to 20260109_160634_quadratic_vertex-工具ClaudeCode模型Opus45/figure.png
diff --git a/20260109_160634_quadratic_vertex-ClaudeCode+Opus45/plot.py b/20260109_160634_quadratic_vertex-工具ClaudeCode模型Opus45/plot.py
similarity index 100%
rename from 20260109_160634_quadratic_vertex-ClaudeCode+Opus45/plot.py
rename to 20260109_160634_quadratic_vertex-工具ClaudeCode模型Opus45/plot.py
diff --git a/20260109_160634_quadratic_vertex-ClaudeCode+Opus45/report.md b/20260109_160634_quadratic_vertex-工具ClaudeCode模型Opus45/report.md
similarity index 100%
rename from 20260109_160634_quadratic_vertex-ClaudeCode+Opus45/report.md
rename to 20260109_160634_quadratic_vertex-工具ClaudeCode模型Opus45/report.md
diff --git a/20260109_160634_quadratic_vertex-ClaudeCode+Opus45/solve.py b/20260109_160634_quadratic_vertex-工具ClaudeCode模型Opus45/solve.py
similarity index 100%
rename from 20260109_160634_quadratic_vertex-ClaudeCode+Opus45/solve.py
rename to 20260109_160634_quadratic_vertex-工具ClaudeCode模型Opus45/solve.py
diff --git a/20260109_161620_quadratic_vertex-工具openode模型MiniMax21/figure.png b/20260109_161620_quadratic_vertex-工具openode模型MiniMax21/figure.png
new file mode 100644
index 0000000..5c18ba3
Binary files /dev/null and b/20260109_161620_quadratic_vertex-工具openode模型MiniMax21/figure.png differ
diff --git a/20260109_161620_quadratic_vertex-工具openode模型MiniMax21/plot.py b/20260109_161620_quadratic_vertex-工具openode模型MiniMax21/plot.py
new file mode 100644
index 0000000..74abdad
--- /dev/null
+++ b/20260109_161620_quadratic_vertex-工具openode模型MiniMax21/plot.py
@@ -0,0 +1,66 @@
+# /// script
+# requires-python = ">=3.11"
+# dependencies = ["numpy", "matplotlib"]
+# ///
+
+import numpy as np
+import matplotlib.pyplot as plt
+
+plt.rcParams["font.sans-serif"] = [
+ "WenQuanYi Micro Hei",
+ "Noto Sans CJK SC",
+ "Microsoft YaHei",
+ "DejaVu Sans",
+]
+plt.rcParams["axes.unicode_minus"] = False
+
+fig, ax = plt.subplots(figsize=(10, 7), dpi=150)
+
+x = np.linspace(-1, 5, 500)
+y = -2 * x**2 + 8 * x - 3
+
+ax.plot(x, y, "b-", linewidth=2, label="$y = -2x^2 + 8x - 3$")
+
+vertex_x, vertex_y = 2, 5
+ax.scatter(
+ [vertex_x],
+ [vertex_y],
+ color="red",
+ s=150,
+ zorder=5,
+ label=f"顶点 ({vertex_x}, {vertex_y})",
+)
+ax.annotate(
+ f"顶点 ({vertex_x}, {vertex_y})\n最大值: y = {vertex_y}",
+ xy=(vertex_x, vertex_y),
+ xytext=(vertex_x + 0.8, vertex_y + 1.5),
+ fontsize=11,
+ ha="left",
+ arrowprops=dict(arrowstyle="->", color="red", lw=1.5),
+ bbox=dict(boxstyle="round,pad=0.3", facecolor="yellow", alpha=0.7),
+)
+
+ax.axhline(y=0, color="gray", linestyle="--", linewidth=1, alpha=0.7)
+ax.axvline(x=0, color="gray", linestyle="--", linewidth=1, alpha=0.7)
+ax.axvline(
+ x=vertex_x,
+ color="green",
+ linestyle=":",
+ linewidth=1.5,
+ alpha=0.7,
+ label=f"对称轴 x = {vertex_x}",
+)
+
+ax.set_xlabel("x", fontsize=12)
+ax.set_ylabel("y", fontsize=12)
+ax.set_title("二次函数 $y = -2x^2 + 8x - 3$ 的图像", fontsize=14, fontweight="bold")
+ax.legend(loc="upper right", fontsize=10)
+ax.grid(True, alpha=0.3)
+
+ax.set_xlim(-0.5, 5.5)
+ax.set_ylim(-6, 8)
+
+plt.tight_layout()
+plt.savefig("figure.png", bbox_inches="tight", dpi=150)
+plt.close()
+print("图像已保存: figure.png")
diff --git a/20260109_161620_quadratic_vertex-工具openode模型MiniMax21/report.md b/20260109_161620_quadratic_vertex-工具openode模型MiniMax21/report.md
new file mode 100644
index 0000000..c0b69b6
--- /dev/null
+++ b/20260109_161620_quadratic_vertex-工具openode模型MiniMax21/report.md
@@ -0,0 +1,80 @@
+# 二次函数 $y=-2x^2+8x-3$ 求解报告
+
+## 1. 🎯 问题描述
+
+已知二次函数 $y = -2x^2 + 8x - 3$,求:
+1. 函数的顶点坐标
+2. 函数的最大值
+
+## 2. ✅ 最终结论
+
+二次函数 $y = -2x^2 + 8x - 3$ 的顶点坐标为 $(2, 5)$,由于抛物线开口向下,该顶点即为函数的最大值点,因此函数的最大值为 $y = 5$。
+
+## 3. 📈 可视化
+
+
+
+**图表说明**:
+
+- 蓝色曲线:函数 $y = -2x^2 + 8x - 3$ 的图像
+- 红色圆点:顶点位置 $(2, 5)$,也是函数的最大值点
+- 绿色虚线:对称轴 $x = 2$
+- 灰色虚线:坐标轴参考线
+
+## 4. 🧠 数学建模与解题过程
+
+
+点击展开
+
+**问题分析**:这是一个标准的一元二次函数 $y = ax^2 + bx + c$ 的求极值问题。
+
+**方法选择**:使用顶点公式法。对于二次函数 $y = ax^2 + bx + c$,其顶点横坐标为 $x = -\frac{b}{2a}$,顶点纵坐标为函数在该点的函数值。
+
+**推导过程**:
+
+已知函数:
+$$y = -2x^2 + 8x - 3$$
+
+其中 $a = -2$,$b = 8$,$c = -3$。
+
+**步骤 1:求顶点横坐标**
+
+$$x_{vertex} = -\frac{b}{2a} = -\frac{8}{2 \times (-2)} = -\frac{8}{-4} = 2$$
+
+**步骤 2:求顶点纵坐标**
+
+将 $x = 2$ 代入原函数:
+$$y_{vertex} = -2(2)^2 + 8(2) - 3 = -2 \times 4 + 16 - 3 = -8 + 16 - 3 = 5$$
+
+**步骤 3:判断极值类型**
+
+由于二次项系数 $a = -2 < 0$,抛物线开口向下,因此顶点为最高点,即函数的最大值点。
+
+**结论**:
+- 顶点坐标:$(2, 5)$
+- 函数最大值:$y = 5$
+
+
+
+## 5. 📊 运行结果
+
+
+点击展开
+
+```
+==================================================
+二次函数 y = -2x² + 8x - 3 求解结果
+==================================================
+
+1. 顶点坐标: (2, 5)
+ 即: x = 2.0, y = 5.0
+
+2. 函数最大值: y = 5.0
+ 由于 a = -2 < 0,抛物线开口向下,
+ 顶点为最高点,即为最大值点。
+
+3. 对称轴: x = 2.0
+==================================================
+```
+
+
diff --git a/20260109_161620_quadratic_vertex-工具openode模型MiniMax21/solve.py b/20260109_161620_quadratic_vertex-工具openode模型MiniMax21/solve.py
new file mode 100644
index 0000000..632e30c
--- /dev/null
+++ b/20260109_161620_quadratic_vertex-工具openode模型MiniMax21/solve.py
@@ -0,0 +1,26 @@
+# /// script
+# requires-python = ">=3.11"
+# dependencies = ["sympy"]
+# ///
+
+import sympy as sp
+
+x = sp.symbols("x", real=True)
+
+a, b, c = -2, 8, -3
+
+y = a * x**2 + b * x + c
+
+vertex_x = -b / (2 * a)
+vertex_y = a * vertex_x**2 + b * vertex_x + c
+
+print("=" * 50)
+print("二次函数 y = -2x² + 8x - 3 求解结果")
+print("=" * 50)
+print(f"\n1. 顶点坐标: ({sp.nsimplify(vertex_x)}, {sp.nsimplify(vertex_y)})")
+print(f" 即: x = {vertex_x}, y = {vertex_y}")
+print(f"\n2. 函数最大值: y = {vertex_y}")
+print(f" 由于 a = -2 < 0,抛物线开口向下,")
+print(f" 顶点为最高点,即为最大值点。")
+print(f"\n3. 对称轴: x = {vertex_x}")
+print("=" * 50)